(1)x^2+1/x^2-3(x+1/x)+4=0 (2)3x^2-12x-2√(x^2-4x+7)+13=0

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(1)x^2+1/x^2-3(x+1/x)+4=0 (2)3x^2-12x-2√(x^2-4x+7)+13=0
(1)x^2+1/x^2-3(x+1/x)+4=0 (2)3x^2-12x-2√(x^2-4x+7)+13=0

(1)x^2+1/x^2-3(x+1/x)+4=0 (2)3x^2-12x-2√(x^2-4x+7)+13=0
(1)x^2+1/x^2-3(x+1/x)+4=0
x²+2x*1/x+1/x²-3(x+1/x)+2=0
(x+1/x)²-3(x+1/x)+2=0
(x+1/x-2)(x+1/x-1)=0
x+1/x=2 x+1/x=1
解这两个方程得x=1
检验:x=1是方程的根
∴方程的根是x=1
(2)3x^2-12x-2√(x^2-4x+7)+13=0
3(x²-4x+7)-2√ (x²-4x+7) -8=0
[3√(x²-4x+7)+4][√(x²-4x+7)-2]=0
∴(x²-4x+7)=4
x=1 或x=3
检验:x=1 x=3是方程的根
∴方程的解是x=1,x=3

(1)x^2+1/x^2-3(x+1/x)+4=0
x²+2x*1/x+1/x²-3(x+1/x)+2=0
(x+1/x)²-3(x+1/x)+2=0
(x+1/x-2)(x+1/x-1)=0
x+1/x=2 x+1/x=1
解这两个方程得x=1
检验:x=1是方程的根
∴方程的根是x=1
(2...

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(1)x^2+1/x^2-3(x+1/x)+4=0
x²+2x*1/x+1/x²-3(x+1/x)+2=0
(x+1/x)²-3(x+1/x)+2=0
(x+1/x-2)(x+1/x-1)=0
x+1/x=2 x+1/x=1
解这两个方程得x=1
检验:x=1是方程的根
∴方程的根是x=1
(2)3x^2-12x-2√(x^2-4x+7)+13=0
3(x²-4x+7)-2√ (x²-4x+7) -8=0
[3√(x²-4x+7)+4][√(x²-4x+7)-2]=0
∴(x²-4x+7)=4
x=1 或x=3
检验:x=1 x=3是方程的根
∴方程的解是x=1,x=3

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