x+y=8,x+z=10,y+x=12,那么x+2y+x=?

x+y=8 y+z=12 x+z=10 x+y+z= x+y=8 y+z=12 x+z=10 x+y+z= (x+y-z)(x-y+z)= (x+y+z)÷10=x+1.1 y+x=z-80+y-1 z-y=8x+y+8 x+z÷y=? (4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=? 已知x+y=8,y+z=12,x+z=10,则x+y+z=? 若x+y=8 y+z=12 x+z=10 则x+y+z =多少 已知x+y=8,x+z=12,x+z=10,则x+Y+z等于几? 已知x+y=8,y+x=12,x+z=10,则x+y+z等于几? (4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian X+Y+Z=? X=3z X+y+z=12 X+2y-2z=10 x/y=(x+z)/(y+z)y/z=(x+y)/(x+z) z+=x>y?++x: 若X/10=Y/8=Z/9则X+Y+Z/Y+Z=? X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z 已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=? (y+z)/x=(z+x)/y=(x+y)/z求x+y-z/x+y+z的值