x^2-2xy+2y^2+4y+4=0,求x^y,3Q
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x^2-2xy+2y^2+4y+4=0,求x^y,3Q
x^2-2xy+2y^2+4y+4=0,求x^y,3Q
x^2-2xy+2y^2+4y+4=0,求x^y,3Q
即(x²-2xy+y²)+(y²+4y+4)=0
(x-y)²+(y+2)²=0
所以
x-y=0,y+2=0
所以 x=y=-2
所以原式=(-2)^(-2)=1/4
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