3x-4/x+2≥1
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3x-4/x+2≥1
3x-4/x+2≥1
3x-4/x+2≥1
3x-4/x+2≥1
3x-4≥x+2
3x-6≥x
2x≥6
x≥3
移项,通分,变成(2X-6)/(X+2)≥0
分子分母乘积大于等于0
注意分母不为零
答案是(-∞,-2)∪[3,+∞)
首先将1移项至不等式的左边并化为x+2/x+2,整理得2x-6/x+2≥0;则(2x-6)(x+2)≥0且x+2不等于零,即2x-6≥0且x+2>0,或2x-6<=0且x+2<0;所以x≥3或x<-2
((3x+6)-10)/x+2 >=1 ->>>> 3(x+2)/(x+2)-10/(x+2) >=1 ->>>>
2>=10/(x+2) ->>>>> x+2>=5 >>> x>=3
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