2x=3y 2y=3z x+y+2z=400 只能是正数求出X,Z
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/31 22:29:00
2x=3y 2y=3z x+y+2z=400 只能是正数求出X,Z
2x=3y 2y=3z x+y+2z=400 只能是正数
求出X,Z
2x=3y 2y=3z x+y+2z=400 只能是正数求出X,Z
x=3y/2
x=2y/3
3y/2+y+4y/3=400
9y+6y+8y=2400
23y=2400
y=2400/23
x=3600/23
x=1600/23
x=3/2y
z=2/3y
3/2y+y+4/3y=400
所以 y=2400/23
x=3/2y=3600/23
z=2/3y=1600/23
X=3Y/2
Z=2Y/3
3Y/2+Y+2Y/3=400
Y=2400/19
X=3600/19
Z=1600/19
两边乘以6
6X+6Y+12Z=2400
3*2X+6Y+4*3Z=2400
9Y+6Y+8Y=2400
Y=2400/23
X=3/2*Y=7200/46
Z=2/3*Y=1600/23
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
2x+z=10 x+y-z=4 3x-y-z=0
x/2=y/3=z/5 x+3y-z/x-3y+z
若x+y+z=3y=2z,则x/x+y+z=?
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
(4x-2y-z)-{5x-[8y-2z-(x+y)]-2(3y-10z)}=?好难啊
3x-y+z=4,2z+3y-z=12,x+y+z=6的解
x+y+z=6 x+2y+3z=14 y+1=z
x+y=5 2x+3y-z=9 x-y+z=4
{2x+y=10 {x-y+z=4 {3x-y-z=0
X/10=Y/8=Z/9,则X+Y+Z/2Y-3Z
x/2=y/3=z/4,则x+2y-z/z=?