（-1）+2+（-3）+4+······+（-2009）+2010+（-2011）=________________________(注意：

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（-1）+2+（-3）+4+······+（-2009）+2010+（-2011）=________________________(注意：
（-1）+2+（-3）+4+······+（-2009）+2010+（-2011）=________________________
(注意：

（-1）+2+（-3）+4+······+（-2009）+2010+（-2011）=________________________(注意：
解析

负奇数相加=1006x-2012
偶数项相加1005x2012

所以
他们相加（1005x2012-1006x2012）÷2
=2012(1005-1006)÷2
=-2012÷2
=-1006

希望对你有帮助
学习进步O(∩_∩)O谢谢

两个一组相加=1，一共1005组 如-1+2=1 -3+4=1
则有(—1)+(+2)—3+4—5········+(—2009)+2010—2011
=(2-1)+(4-3)+...+(-2011)
=（1+1+...+1）-2011
=1*1005-2011
=-1006

=1+1+……+1+（-2011）【共2010/2 个1】
=1005-2011=-1006

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