2/X +3/Y=2(X>0 Y>0) 则XY最小值为
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2/X +3/Y=2(X>0 Y>0) 则XY最小值为
2/X +3/Y=2(X>0 Y>0) 则XY最小值为
2/X +3/Y=2(X>0 Y>0) 则XY最小值为
2/X +3/Y>=2√6/xy
2>=2√6/xy
1>=√6/xy
x^2y^2>=6xy
xy>=6
所以最小是6
楼上带公式忘了一个2
是x+y>=2√xy
所以最小应该是6
3
通分2XY=3X+2Y>=2根号(6xy)
2根号(xy)(根号xy-根号6)>=0.
xy>=6
7y(x-3y)-2(3y-x)=0 .x=?,y=?
先化简,再求值 [2/3x - 2/x+y(x+y/3x -x-y)]*x/x-y,其中5x+3y=0
先化简,再求值:[3x-2/x+y(x+y/3x-x-y)]/(x-y/x),其中5x+3y=0
若3x-5y=0,则x+y/x=(),x-y/y=(),2x-3y/2x+3y=( )
已知x-3y=0,求(2x+y)/(x^2-2xy+y^2)X(x-y)
已知2x-y=0,求分式【1+(3*y*y*y/x*x*x-y*y*y)】/【1+(2y/x-y)】的值注:x*x*x-y*y*y=(x-y)*(x*x+xy+y*y)
{4x-3y-10=0 3x-2y=0,{3x-4(x-y)=2 2x-3y=1,{2(x+y)-(x-y)=3 (x+y)-2(x-y)=1
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
已知x>0,Y>0,如何证x^2/y+y^2/x>=x+y
(X,Y) f(x,y)={12y^2,0
x*x+2x+y*y-4y+5=0 x= y=
设Z=X+Y,其中X,Y满足X+2Y>=0,X-Y
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
(x+y-5)*(x+y-5)+(x-y+3)=0 x*x-y*y
已知:3x-5y=0,求x/y,x-y/y,x-y/x
x^2+4y^2-6x+4y+10=0,求x^4-y^4/(x+2y)(x-2y)*x+2y/xy^2+y^3除以(x^2+y^2/y)^2的值
(5)若x/2=y/3(y不为0)则x/y=____,x+y/y=___,y/x-y=___.