已知2x^2+4x+y^2=2xy-4,求x^y的值

已知2x^2+4x+y^2=2xy-4,求x^y的值
已知2x^2+4x+y^2=2xy-4,求x^y的值

已知2x^2+4x+y^2=2xy-4,求x^y的值
2x^2+4x+y^2=2xy-4
2x^2+4x+y^2-2xy+4=0
(x+2)^2+(x-y)^2=0
所以x=-2,y=-2
所以x^y=(-2)^(-2)=1/4

(x^2+4x+4)+(x^2-2xy+y^2)=0
(x+2)^2+(x-y)^2=0
x+2=0且 x-y=0
x=-2 ，y=-2
x^y=(-2)^(-2)=1/4