x^2+2xy-3y^2+3x+y+2因式分解
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x^2+2xy-3y^2+3x+y+2因式分解
x^2+2xy-3y^2+3x+y+2
因式分解
x^2+2xy-3y^2+3x+y+2因式分解
你一定是一个初中生吧,那你应该知道十字相乘法
x^2+2xy-3y^2+3x+y+2
=(x^2+2xy-3y^2)+x+3y+2x-2y+2
=(x+3y)(x-y)+(x+3y)+2(x-y+1)
=(x+3y)(x-y+1)+2(x-y+1)
=(x+3y+2)(x-y+1)
支持一楼楼主!!!
(x+3y+2)(x-y+1)
此类题目可以用待定系数法求解.
过程如下:
设(x+ay+b)(x+cy+d)
由已知得:a+c=2
ac=-3
bd=2
b+d=3
解得a=3,b=2,c=-1,d=1
即上述答案.
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