(x-1)*(x-1)+(y+2)*(y+2)=0求(x+y)的2010次方
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(x-1)*(x-1)+(y+2)*(y+2)=0求(x+y)的2010次方
(x-1)*(x-1)+(y+2)*(y+2)=0求(x+y)的2010次方
(x-1)*(x-1)+(y+2)*(y+2)=0求(x+y)的2010次方
x-1=0
y+2=0
∴x=1
y=-2
(x+y)^2010=(1-2)^2010=1
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