(1)x^2+x-5=0 (2)x^2-(3/2)x+3=0
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(1)x^2+x-5=0 (2)x^2-(3/2)x+3=0
(1)x^2+x-5=0 (2)x^2-(3/2)x+3=0
(1)x^2+x-5=0 (2)x^2-(3/2)x+3=0
嬲,这么容易(1)公式法a=1 b=1 c=-5 b^2-4ac=21 所以x1 x2 =2a/-b+根号下面b^2-4ac=1+-根号21 (2)这题也用公式法,好解
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5/x^2+x - 1/x^2-x=0
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
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