若2x+5y+4z=0,3x+y-7z=0,则x+y-z的值等于
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若2x+5y+4z=0,3x+y-7z=0,则x+y-z的值等于
若2x+5y+4z=0,3x+y-7z=0,则x+y-z的值等于
若2x+5y+4z=0,3x+y-7z=0,则x+y-z的值等于
2x+5y+4z=0 式①
3x+y-7z=0 式②
x+y-z=?
式①×3-式②×2
3(2x+5y+4z)-2(3x+y-7z)=0
15y+12z-2y+14z=0
13y+26z=0 式③
式①-式②×5
(2x+5y+4z)-5(3x+y-7z)=0
-13x+39z=0 式④
由式③得
y=-2z
由式④得
x=3z
将式③式④代入原式中
所以:
x+y-z=3z+(-2z)-z=0
所以答案为:0
答案是0 ,,,,,,,
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