2x+2-3y+3=10/2x+2+7y-7=20这个方程组怎么解?
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2x+2-3y+3=10/2x+2+7y-7=20这个方程组怎么解?
2x+2-3y+3=10/2x+2+7y-7=20这个方程组怎么解?
2x+2-3y+3=10/2x+2+7y-7=20这个方程组怎么解?
2x-3y=5/2x+7y=25
10y=20
y=2
x=11/2
两者相减得10Y-10=10
Y=2
X=11/2
2x+2-3y+3=10 (1)
2x+2+7y-7=20 (2)
(1)-(2)得
-10y+10=-10
-10y=-20
y=2
将y=2代入(1)得
x=5.5
2x+2-3y+3=10移项后可得2X=5+3Y 将此式带入2x+2+7y-7=20得5+3Y+2+7Y-7=20 然后合并整理可得10Y=20 得y=2 由于2X=5+3Y 所以2x=11 x=5.5 所以x=5.5 y=2
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