已知x,y满足x＾2+4y＾2+2x-4y+2=0,则根号5x＾2+16y＾2=?

已知x,y满足x＾2+4y＾2+2x-4y+2=0,则根号5x＾2+16y＾2=?
已知x,y满足x＾2+4y＾2+2x-4y+2=0,则根号5x＾2+16y＾2=?

已知x,y满足x＾2+4y＾2+2x-4y+2=0,则根号5x＾2+16y＾2=?
x^2+4y^2+2x-4y+2=0
(x+1)^2+(2y-1)^2=0
x+1=0,2y-1=0
x=-1,y=1/2
√5x^2+16y^2=√(5*(-1))^2+16*(1/2)^2
=5+16*1/4
=5+4=9
是否可以解决您的问题?

x^2+4y^2+2x-4y+2=0
x^2+2x+1+4y^2-4y+1=0
(x+1)^2+(2y+1)^2=0
x=-1 y=-1/2
5x^2+16y^2=5*(-1)^2+16*(-1/2)^2=5+4=9