若(x+y-7)^2+|x^2-y^2-56|=0,则x-y的值为________
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若(x+y-7)^2+|x^2-y^2-56|=0,则x-y的值为________
若(x+y-7)^2+|x^2-y^2-56|=0,则x-y的值为________
若(x+y-7)^2+|x^2-y^2-56|=0,则x-y的值为________
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若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
化简y(x+y)+(x+y)(x-y)-x^2
化简3(x-y)-7(x--y)+2(y-x)
(x+y)(x-y)-(x-y)^2如题 (x+y)(x-y)-(x-y)^2
【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y)
因式分解x(x+y)(x-y)-x(x+y)^2
[(x-y)^2-(x+2y)(x-2y)]/y
计算:y-x分之x+y+x-y分之y-y-x分之2x-y
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
[(x+2y)²-(x+y)(x-y)-7y²】÷(2y)
x^2(x-y)+(y-x)
x(x-y)2-(y-x)3
【(x-y)^2+(x+y)(x-y)】除以 2x
[(x-y)²+(x+y)(x-y)]除以2x
x+2y=2x+y+1=7x-y 求:2x-y?
解方程组(x+y)(x-2y)=-5 (x-y)(x+2y)=7
(x-y)^2+7(x+y)-11(x-y)^2-8(x+y),先化简.再求值