已知|a-2|+(b-1)²+|c|=0,求a²-2ab-5a²+12ac+3ab-c²-8ac-2a²的值

已知|a-2|+(b-1)²+|c|=0,求a²-2ab-5a²+12ac+3ab-c²-8ac-2a²的值
已知|a-2|+(b-1)²+|c|=0,求a²-2ab-5a²+12ac+3ab-c²-8ac-2a²的值

已知|a-2|+(b-1)²+|c|=0,求a²-2ab-5a²+12ac+3ab-c²-8ac-2a²的值
|a-2|+(b-1)²+|c|=0,
则,a=2,b=1,c=0
a²-2ab-5a²+12ac+3ab-c²-8ac-2a²
= -6a²+ab+4ac-c²
=-6×2²+2×1+4×1×0-0²
=-24+2+0-0
= -22