已知实数x y满足:x^+y^-6x+2y+10=0,求x^-y^的立方根的值急
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已知实数x y满足:x^+y^-6x+2y+10=0,求x^-y^的立方根的值急
已知实数x y满足:x^+y^-6x+2y+10=0,求x^-y^的立方根的值
急
已知实数x y满足:x^+y^-6x+2y+10=0,求x^-y^的立方根的值急
是x²+y²-6x+2y+10=0吗?
如果是的话,方程可写为:(x-3)²+(y+1)²=0,∵(x-3)²≥0,(y+1)²≥0,∴(x-3)²=(y-1)²=0,即:x=3,y=-1;所以x²-y²=9-1=8,即³√(x²-y²)=³√8=2.
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