解方程组x-2y=4,2x+y-3=0
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解方程组x-2y=4,2x+y-3=0
解方程组x-2y=4,2x+y-3=0
解方程组x-2y=4,2x+y-3=0
x-2y=4(式1),2x+y-3=0,2x+y=3,4x+2y=6(式2),式1+式2,5x=10,x=2,代入2x+y-3=0,4+y-3=0,y=-1 .
x-2y=4 ①
2x+y-3=0 ②
②×2得4x+2y=6 ③
①+③得5x=10
x=2
把x=2代入①得2-2y=4
2y=-2
y=-1
所以原方程组的解是x=2,y=-1
x-2y=4 ①,2x+y-3=0 ②
①+②×2,得
(x-2y)+2(2x+y-3)=4
5x=10
x=2
将x=2代入①,得
2-2y=4
y=-1
解得:x=2,y=-1
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