xy-2/3y-2/3-1/2x+1/2xy-1合并同类项的值
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xy-2/3y-2/3-1/2x+1/2xy-1合并同类项的值
xy-2/3y-2/3-1/2x+1/2xy-1合并同类项的值
xy-2/3y-2/3-1/2x+1/2xy-1合并同类项的值
原式=(1+1/2)XY-1/2X-2/3Y+(-2/3-1)
=3/2XY-1/2X-2/3Y-5/2.
计算3xy[2xy-x(y-2)+x-1]
xy(xy+1)+xy+3-2(x+y+1/2)-(x+y-1)^2因式分解
(-1/3xy)^2•[xy(2x-y)-2x(xy-y^2)]
(-3分之1xy)的平方×[xy(2x-y)-2x(xy-y的平方)]
XY(XY+3)+(XY+4)+4(X+Y+1)-(X+Y+2)
若1/x-1/y=2,求3x-2xy-3y/x-xy-y的值3x-2xy-3y/x-xy-y 不好意思,是3x-2xy-3y/x-2xy-y
因式分解x^2y^2+x^2y+xy^2+3xy+x+y+1
1、(-7x^y)(2x^y-3xy^3+xy) 2、((x-y)^6)/((y-x)^3)/(x-y)
(-xy^-1)^2*(-xy^-2)^-3/(-x^2y^3)
y^3+xy^2+2xy+x^2-1 因式分解
5x^2y/-1/2xy*3xy^2
( )-(x^2+3xy)=-xy-1/3y^2
5xy^2-{2x^y-[3xy^2-(xy^2-2x^2y)]/(-1/2xy)}
化简!1、(x^2-xy)+xy+y^2 2、3(x^2-xy)-xy+y^2
(x+2y-3xy)-(-2x-y+xy),其中x+y=1/2,xy=-1/2
已知3/(x-y)=1/xy 求(-x-2xy+y)/ (2x+3xy-2y)
已知xy/x+y=1/2,则代数式3x-5xy+3y/-x+3xy-y=
已知1/x-1/y=2,求3x+7xy-3y/2x-3xy-2y答案是1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/7 谁能帮我解释一下=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy) 是怎