若根号x+y-1+(y+3)²=0,求(5x-y)·(2x+3y)的值.急急急!快快快!

若根号x+y-1+(y+3)²=0,求(5x-y)·(2x+3y)的值.急急急!快快快!
若根号x+y-1+(y+3)²=0,求(5x-y)·(2x+3y)的值.
急急急!快快快!

若根号x+y-1+(y+3)²=0,求(5x-y)·(2x+3y)的值.急急急!快快快!
根号x+y-1+(y+3)²=0
则 x+y-1=0,x+y=1
y+3=0,y=-3,x=4
(5x-y)·(2x+3y)
=(20+3)(8-9)
=-23