分解因式x^2+2xy+y^2-4x-4y-5

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分解因式x^2+2xy+y^2-4x-4y-5
分解因式x^2+2xy+y^2-4x-4y-5

分解因式x^2+2xy+y^2-4x-4y-5
x^2+2xy+y^2-4x-4y-5
=(x+y)²-4(x+y)-5
=(x+y)²-4(x+y)+4-9
=(x+y-2)²-9
=(x+y-2)²-3²
=(x+y-5)(x+y+1)

原式=(x+y)^2-4(x+y)-5=(x+y-5)(x+y+1)

您好:

x^2+2xy+y^2-4x-4y-5
=(x+y)²-4(x+y)-5
=(x+y-5)(x+y+1)

不明白,可以追问
如有帮助,记得采纳,谢谢
祝学习进步!

(x+y)^2-4(x+y)-5
(x+y-5)(x+y+1)