1.x²+（2根号5）*5+5=02.x²+12x=93.-x²+4x-3=04.-x²+5x+6=0

1.x²+（2根号5）*5+5=02.x²+12x=93.-x²+4x-3=04.-x²+5x+6=0
1.x²+（2根号5）*5+5=0
2.x²+12x=9
3.-x²+4x-3=0
4.-x²+5x+6=0

1.x²+（2根号5）*5+5=02.x²+12x=93.-x²+4x-3=04.-x²+5x+6=0
x²+（2根号5）*5+5=0, 是否为x²+（2根号5）*x+5=0?

1.x²+2√5*x+5=0(x+√5)²=0
x=-√5

2.x²+12x=9x²+12x-9=0
b²-4ac=12²-4*1*(-9)=180
x=(-b±√(b²-4ac))/4a
=(-12±6√5)/4
=(-6±3√5)/2

3.-x²+4x-3=0x²-4x+3=0
(x-1)(x-3)=0
x=1 x=3

4.-x²+5x+6=0x²-5x-6=0
(x-6)(x+1)=0
x=6 x=-1