y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值…………y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值是?

y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值…………y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值是?
y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值…………
y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值是?

y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值…………y=sin(2x+π/6)+cos(2x+π/3)的最小正周期和最大值是?
sinα+sinβ=2sin[(α+β)/2]cos[(α-β)/2]
y=sin(2x+π/6)+cos(2x+π/3)
=sin(2x+π/6)+sin[π/2-(2x+π/3)]
=sin(2x+π/6)+sin(-2x+π/6)
=2sin(π/6)cos(2x)
=cos(2x)
y=sin(2x+π/6)+cos(2x+π/3)的最大值=1
最小正周期T=2∏/2=∏.