sin^4A+cos^2A+sin^2Acos^2A=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 08:59:48
sin^4A+cos^2A+sin^2Acos^2A=?
sin^4A+cos^2A+sin^2Acos^2A=?
sin^4A+cos^2A+sin^2Acos^2A=?
sin^4a+sin^2acos^2a+cos^2a
=sin^2a(sin^2a+cos^2a)+cos^2a
=sin^2a+cos^2a
=1
sin^4A+cos^2A+sin^2Acos^2A
=sin^4A+cos^2A+sin^2A*(1-sin^2A)
=sin^4A+cos^2A+sin^2A1-sin^4A
=1
sin^4+sin^2cos^2+cos^2a=
求证1+sin a+cos a+2sin acos a/1+sin a+cos a=sin a+cos a
(cos a)^4+(sin a)^2*(sin a)^2+(sin a)^2=?
cosA+cos^2A=1,sin^2A+sin^4A+sin^8A
(1-sin^6a-cos^6a)/(sin^2a-sin^4a)
sin/cos^2a+cos/sin^2a最小值
求证:sin 2a/1+sin a+cos a=sin a+cos a-1急
化简:sin^4a+cos^2a-sin^2a-cos^4a
sin^4a-cos^4a=sin^2a-cos^2a
证明sin^4a-cos^4a=sin^2a-cos^2a
用 cos a表示 sin^4 a-sin^2 a+cos^2 a
tan a =3求4sin a-2cos a/5cos+3sin a
(1-sin^4a-cos^4)/(sin^2a-sin^4a) 化简
化简:sin(-a)cos(2π+a)sin(-a-π)
化简Sin A + Sin 2A / 1+cos A +
sin^4a-cos^4a=sin^2-cos^2a
一个简单的三角函数题(sin a + cos a)/(sin a - cos a) 则 sin a *cos a=(sin a + cos a)/(sin a - cos a) = 2 则 sin a *cos a=
化简(sin a^2/cos a +cos a)*cot a