(3x+2)(3x-2)-5x(x-1)-(2x-1)²,其中√5<x<√10,且x为整数.

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(3x+2)(3x-2)-5x(x-1)-(2x-1)²,其中√5<x<√10,且x为整数.
(3x+2)(3x-2)-5x(x-1)-(2x-1)²,其中√5<x<√10,且x为整数.

(3x+2)(3x-2)-5x(x-1)-(2x-1)²,其中√5<x<√10,且x为整数.
∵√5<x<√10且x为整数
∴x=3
(3x+2)(3x-2)-5x(x-1)-(2x-1)²
=9x²-4-5x²+5x-4x²+4x-1
=9x-5
当x=3时
原式=27-5=22

因为x是整数,所以X=3,带入得原式=22

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