解方程 2t³+3t²+3t+1

解方程 2t³+3t²+3t+1
解方程 2t³+3t²+3t+1

解方程 2t³+3t²+3t+1
2t³+3t²+3t+1
=2t³+t²+2t²+3t+1
=t²(2t+1)+(t+1)(2t+1)
=(2t+1)(t²+t+1)=0
t²+t+1=0无解
所以t=-1/2

整体除以2t+1，得到t2+t+1，即2t3+3t2+3t+1=(2t+1)(t2+t+1)

-1/2
-1/2 + √3/2 i
-1/2 - √3/2 i