1/1×3+1/3×5+1/5×7+1/7×9+……+1/49×51还有1/1×2×3+1/2×3×4+1/3×4×5+1/4×5×6+……1/48×49×50都用简便计算

来源：学生作业帮助网编辑：作业帮时间：2024/11/15 07:03:38

1/1×3+1/3×5+1/5×7+1/7×9+……+1/49×51还有1/1×2×3+1/2×3×4+1/3×4×5+1/4×5×6+……1/48×49×50都用简便计算
1/1×3+1/3×5+1/5×7+1/7×9+……+1/49×51
还有
1/1×2×3+1/2×3×4+1/3×4×5+1/4×5×6+……1/48×49×50
都用简便计算

1/1×3+1/3×5+1/5×7+1/7×9+……+1/49×51还有1/1×2×3+1/2×3×4+1/3×4×5+1/4×5×6+……1/48×49×50都用简便计算
第一道题实在不想说.太简单了.自己试吧
第二道题给你点思路.
1/1 X 2 X 3+1/2 X 3 X 4,你看,分母2可以和前面的2消掉,原式就为,3^2+4
同理,1/1×2×3+1/2×3×4+1/3×4×5=3+4^2+5
再同理,1/1×2×3+1/2×3×4+1/3×4×5+1/4×5×6=3+4+5^2+6
发现规律了吧.
原式=3+4+5+6+7+8+……+49^2+50
这个又可以变换成3+4+5+6+7+8+……+49+50+49 X 48
即(3+50)/2 X 48+49 X 48
OK,然后答案就出来了,我懒得用计算器了.

靠。。抱歉看错题。。重新回复。。

1-3+5-7+... (1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7) 简算(1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7) 简便计算 1/1*3+1/1*3*5+1/1*3*5*7+1/1*3*5*7*9-73/945 1/3+1/5+1/7+.+1/2n+1 (1/3+1/5+1/7)*(1/5+1/7+1/9)-(1/3+1/5+1/7+1/9)*(1/5+1/7)=? 1 1 1 1 1 3 5 7 1 5 13 25 1 7 25 why 1/1×3+1/3×5+1/5×7+1/7×9.+1/2011×2013 简算:1/1*3+1/3*5+1/5*7+1/7*9+1/9*11 1/1*3+1/3*5+1/5*7+1/7*9+...1/17*19= 计算1/(1×3)+1/(3×5)+1/(5×7)+1/(7×9)+.+1/(19×21) 1/1×3+1/3×5+1/5×7+1/7×9+.+1/2013×2015 1/1*3+1/3*5+1/5*7+1/7*9+.+1/101*103 帮帮忙1/1*3+1/3*5+1/5*7+1/7*9+...1/99*101 1/1*3+1/3*5+1/5*7+1/7*9+1/49*51= 计算：1/1×3+1/3×5+1/5×7+1/7×9``````+1/2001×2003 (1*3)/1+(3*5)/1+(5*7)/1+(7*9)/1+(9*11)/1 1/1*3+1/3*5+1/5*7+1/7*9+1/9*11 (1*3)/1+(3*5)/1+(5*7)/1+(7*9)/1+(9*11)/1