(x+2)(x+3)(x+4)(x+6)-42x^2换元法,
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(x+2)(x+3)(x+4)(x+6)-42x^2换元法,
(x+2)(x+3)(x+4)(x+6)-42x^2
换元法,
(x+2)(x+3)(x+4)(x+6)-42x^2换元法,
原式=[(x+2)(x+6)][(x+3)(x+4)]-42x²
=[(x²+12)+8x][(x²+12)+7x]-42x²
=(x²+12)²+15x²(x²+12)+56x²-42x²
=(x²+12)²+15x²(x²+12)+14x²
=(x²+x+12)(x²+14x+12)
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