数列an满足a1=1,an=2an-1/(2+an-1) (n≥2),用数学归纳法求an的通项公式?

数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 数列{an}满足a1=1 an+1=2n+1an/an+2n 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 数列an满足a1=2,an+1=4an+9,则an=? 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 数列an满足a1=2,an+1=an²求an 数列an满足a1=2,an+1=an²求an 已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an 已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列 已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an 已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an 数列{an}满足:a1=1,an>0,an+1^2-an^2=1,那么an 数列{an}满足:a1=1,an>0,an+1^2-an^2=1,那么an 知数列{an}满足a1=-2,an+1(下标）=2+2an/(1-an),则an为? 已知数列｛an｝满足a1=1,an+1 -an+2an+1•an=0求通项 已知数列{an}满足a1=2,an+1-an=an+1*an,那么a31等于 数列an满足,a1=8且8an+1an-16an+1+2an+5=0 数列an满足an+1=根号(an^2+1)+an,a1=a>0,求an通项公式