已知数列｛an｝满足a1=1,an=1-1/4a(n-1) (n≥2),设bn=2/2an-1（下标为n),(1)求证：数列｛bn｝是等差数列.（2）数列｛an｝的通项公式 （3)若数列｛bn｝的前n项和为Sn,求(an*Sn)/n^2的极限过程详细

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