∫(0,2) (4-2x)(4-x^2)dx 定积分如何计算
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∫(0,2) (4-2x)(4-x^2)dx 定积分如何计算
∫(0,2) (4-2x)(4-x^2)dx 定积分如何计算
∫(0,2) (4-2x)(4-x^2)dx 定积分如何计算
∫(0,2) (4-2x)(4-x^2)dx
=∫(0,2) (16-8x-4x^2+2x^3)dx
=[16x-4x^2-(4/3)x^3+(1/2)x^4]|(0,2)
=40/3
先化简得
16-4X^2-8X-2X^3
再用定积分求就可以
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