1/(x+1)+1/(x+5)=1/(x+2)+1/(x+4) 这题怎么做?
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1/(x+1)+1/(x+5)=1/(x+2)+1/(x+4) 这题怎么做?
1/(x+1)+1/(x+5)=1/(x+2)+1/(x+4) 这题怎么做?
1/(x+1)+1/(x+5)=1/(x+2)+1/(x+4) 这题怎么做?
1/ (x+1) + 1/(x+5) = 1/(x+2) + 1/(x+4)==> 1/ (x+1) - 1/(x+2)= 1/(x+4) - 1/(x+5)
==> 1/[(x+1)(x+2)] = 1/[(x+4)(x+5)]
==> (x+1)(x+2) = (x+4)(x+5)
==> x^2 + 3x + 2 = x^2 + 9x + 20
==> 6x = -18
==> x = -3
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