(1-1/2)*(1-1/3)*(1-1/4)*……*(1-1/100)=====
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(1-1/2)*(1-1/3)*(1-1/4)*……*(1-1/100)=====
(1-1/2)*(1-1/3)*(1-1/4)*……*(1-1/100)
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(1-1/2)*(1-1/3)*(1-1/4)*……*(1-1/100)=====
=1/2×2/3×3/4×4/5×...×98/99×99/100
相邻两个分数的分子和分母正好约掉
最后分子剩1,分母还剩100
所以结果为1/100
(1-1/2)*(1-1/3)*(1-1/4)*……*(1-1/100)
=(1/2)*(2/3)*(3/4)*...*(99/100)
=1/100
(1-1/2)*(1-1/3)*(1-1/4)*……*(1-1/100)
=1/2*2/3*3/4**……*99/100 前一个分数的分母可以和后一个分数的分子约分
=1/100
200*(1-1/2)*(1-1/3)*(1-1/4)*.*(1-1/100)
(1-2/1)*(1-3/1)*(1-4/1)*.*(1-2007/1)*(1-2008/1)
(1/2014-1)(1/2013-1)(1-2012-1)...(1/3-1)(1/2-1)
(1/2+1/3+...+1/2004)(1+1/2+1/3+...+1/2003)-(1+1/2+1/3+...+1/2004)(1/2+1/3+...+1/2003)
2000*(1-1/2*)*(1-1/3)*...*(1-1999)*(1-1/2000)
2000*(1-1/2)*(1-1/3)*.*(1-1/1999)*(1-1/2000)
(1-1/2004)(1-2003)(1-2002)…(1-1/3)(1-1/2)
(1-1/2)(1-1/3)(1-1/4).(1-1/100)
计算:(-1)-[1-(1-1/2*1/3)]*6
计算!(-1)-[1-(1-1/2*1/3)]*6
(1+2/1)(1+4/1)(1+6/1).(1+10/)(1-3/1)(1—5/1).(1-9/1)
巧算(奥数题)问:(1+1/2)×(1-1/2)×(1+1/3)×(1-1/3)×...(1+1/99)×(1-1/99)
计算 ( 1+1/2)*(1-1/3)*(1+1/4)*(1-1/5)*.*(1+1/1000)*(1-1/1001)
(1+1/2)*(1-1/2)*(1+1/3)*(1-1/3)*...(1+1/2006)*(1-1/2006)怎么简算呀?
(1+1/2)*(1-1/2)*(1+1/3)*(1-1/3)*……*(1+1/99)*(1-1/99)
(1+1/2)×(1-1/2)×(1+1/3)×(1-1/3)×...×(1+1/99)×(1-1/99)=?
(1+1/2)×(1-1/2)×(1+1/3)×(1-1/3)×……×(1+1/99)×(1-1/99)=
(1+1/2)*(1-1/2)*(1+1/3)*(1-1/3)*.(1+1/9)*(1-1/9)