x趋向于0,lim ln（1+x)/x^2运用等价无穷小化为1/x,所以答案为无穷大?这样做对吗

x趋向于0+,lim(ln(tan4x)/ln(tanx)) lim ln(sinx/x)的极限.x趋向于0 lim x趋向于0 [ln(1+x)/x]^[1/(e^x-1)] lim ln(1+2x)/e^x x趋向于0 e^x x趋向0 lim [ ln (1-x) / (e ^ x-1 ) ] lim(ln(1+x)/x) x趋向0 lim(x趋向0)ln(1+sin x)/x^2 求极限lim(x趋向于0)ln(1+x^2)/sin(1+x^2) lim(1+ln(1+x))^(2/x) x趋向于0 x趋向于0,lim[x*ln(1+3x)]/(1-cosx) lim(1+ln(1+x))^(2/x) x趋向于0 x 趋向于0 求lim(cos1/x+2/sinx-1/ln(1+x)) 利用等价无穷小替换 lim 的x趋向于0 ln(1+x)/x是多少? lim(x趋向于0)ln(1/x)^x的解答步骤 lim函数[ln(1/x)]^x(x趋向于0+)的值 lim|x趋向于0+ ln(1+2x^2)/x^2 = 2, lim[cos ln(1+x)-cos ln(x)]x趋向于正无穷 x趋向于0,求lim(sin3x)/ln(1+3x),