若(x+1)^2+4|y-6|=0,则5x+6y+4x-8y的值是
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若(x+1)^2+4|y-6|=0,则5x+6y+4x-8y的值是
若(x+1)^2+4|y-6|=0,则5x+6y+4x-8y的值是
若(x+1)^2+4|y-6|=0,则5x+6y+4x-8y的值是
因为一个数的平方大于等于0
一个数的绝对值也大于等于0
所以只有当 x + 1 = 0 且 y - 6 = 0 时等号才成立
所以 x = -1 ,y = 6
5x + 6y + 4x - 8y
= 9x - 2y
= 9×(-1) - 2×6
= -9 - 12
= -21
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