[(x²-2x+1分之1-x²+2x-+1分之1)]÷(x+1分之1)+[(x-1分之1)],

[(x²-2x+1分之1-x²+2x-+1分之1)]÷(x+1分之1)+[(x-1分之1)],
[(x²-2x+1分之1-x²+2x-+1分之1)]÷(x+1分之1)+[(x-1分之1)],

[(x²-2x+1分之1-x²+2x-+1分之1)]÷(x+1分之1)+[(x-1分之1)],
[(x²-2x+1分之1-x²+2x-+1分之1)]÷(x+1分之1)+[(x-1分之1)]
=[1/(x-1)²-1/(x+1)²]÷[1/(x+1）+1/(x-1)]
=[1/(x+1）+1/(x-1)][1/(x-1）+1/(x+1)]÷[1/(x+1）+1/(x-1)]
=1/(x-1）-1/(x+1)
=(x+1)/(x+1）(x-1)-(x-1)/(x-1)(x+1)
=(x+1-x+1)/(x-1)(x+1)
=2/(x+1)(x-1)

提示：用平方差公式,不要通分