(x+1)(x+2)(x+3)(x+6)-24 用换元法分解因式怎么分解?

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(x+1)(x+2)(x+3)(x+6)-24 用换元法分解因式怎么分解?
(x+1)(x+2)(x+3)(x+6)-24 用换元法分解因式怎么分解?

(x+1)(x+2)(x+3)(x+6)-24 用换元法分解因式怎么分解?
你题目抄错了吧
应该是(x+1)(x+2)(x+3)(x+4)-24因式分解
原式=[(x+1)(x+4)][(x+2)(x+3)]-24
=(x²+5x+4)(x²+5x+6)-24
设A=x²+5x,则
原式=(A+4)(A+6)-24=A²+10A+24-24=A²+10A
原式=A(A+10)
=(x²+5x)(x²+5x+10)
=x(x+5)(x²+5x+10)

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