1.2x^3-3x^2=27x 2.x^3+2x^2-3=0 3.(2x^2-3x+1)^2+4x^2-1=6x
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1.2x^3-3x^2=27x 2.x^3+2x^2-3=0 3.(2x^2-3x+1)^2+4x^2-1=6x
1.2x^3-3x^2=27x 2.x^3+2x^2-3=0 3.(2x^2-3x+1)^2+4x^2-1=6x
1.2x^3-3x^2=27x 2.x^3+2x^2-3=0 3.(2x^2-3x+1)^2+4x^2-1=6x
第一题:x=0或4.5或-3 第二题:x=1 第三题:x=0或1.5
1:x=0或4.5或-3
2:x=1
3:x=0或1.5
x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x
(X+1)X(X+2)X(X+3)=504
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x+x^2+x^3+x^4+x^5+.+x^27=?
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