若4x^2+|x-6|+9y^2=12xy,则x+y= 若4x^2+|x-6|+9y^2=12xy,则x+y=
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若4x^2+|x-6|+9y^2=12xy,则x+y= 若4x^2+|x-6|+9y^2=12xy,则x+y=
若4x^2+|x-6|+9y^2=12xy,则x+y=
若4x^2+|x-6|+9y^2=12xy,则x+y=
若4x^2+|x-6|+9y^2=12xy,则x+y= 若4x^2+|x-6|+9y^2=12xy,则x+y=
即(4x²-12xy+9y²)+|x-6|=0
(2x-3y)²+|x-6|=0
所以2x-3y=0,x-6=0
所以
x=6
y=4
所以x+y=10
解
4x²+|x-6|+9y²=12xy
(4x²-12xy+9y²)+|x-6|=0
(2x-3y)²+|x-6|=0
∴2x-3y=0,x-6=0
∴x=6,y=4
∴x+y=6+4=10
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
计算:1.y/4x²-1/12y²+1/6xy 2.3/x-6/1-x-x+5/x²-x3.x/x-y×y²/x+y-x四次方y/x四次方-y四次方÷x²/x²+y²解方程:1.x-1/(x-2)+1=1/2-x2.x+1/x-1-4/x²-1=13.1/x+3-2/3-x=1/x²-9
若2x^2-6xy+9y^2-4x+4=0,则y/x-x/y=若2x^2-6xy+9y^2-4x+4=0,则y/x-x/y=?
xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
已知X.x+y.y-4x+2y+5=0,求4X.X-12X Y+9Y.y的值
在4x^2+12x+|2y-6|=-9的条件下,x^y=
81/8*(-x-y)^6*(x-y)^3*4/9(x+y)^4*(y-x)^2
(x+y)/2- x-y/2=6 3(x+y)=4(x-y)
x+y/3+x-y/2=6 4(x+y)-2(x-y)=40
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-2(x-y)=11 4(x+y)+3(x-y)=9
若(x-y)/(x+y)=3 则(x+2y)/(6x-7y)等于
x+y/2+x-y/3=6,4(x+y)-3(x-y)=-20
{(x+y)/2+(x-y)/3=6 4(x+y)-3(x-y)=-20
4(x+y)-3(x-y)=-20,2/x+y+3/x-y=6
9(x-y)^2-12(x-y)+4=快
因式分解:4+12(x+y)+9(x-y)^2=?