如果x/3=y/2=z/5,求(2x+3xy-2y)/(x-y+z)的值

如果x/3=y/2=z/5,求(2x+3xy-2y)/(x-y+z)的值
如果x/3=y/2=z/5,求(2x+3xy-2y)/(x-y+z)的值

如果x/3=y/2=z/5,求(2x+3xy-2y)/(x-y+z)的值
令x/3=y/2=z/5=k
则x=3k y=2k z=5k
(2x+3xy-2y)/(x-y+z)
=(6k+18k^2-4k)/(3k-2k+5k)
=(2k+18k^2)/(6k)
=(1+9k)/3
=1/3+3k