作业帮(y+2)(y-2)(y-1)(y+5)平方差计算过程要详细,尤其是(y-1)(y+5),写清楚为什么会得出那个结果,
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(y+2)(y-2)(y-1)(y+5)平方差计算过程要详细,尤其是(y-1)(y+5),写清楚为什么会得出那个结果,
(y+2)(y-2)(y-1)(y+5)平方差计算过程要详细,尤其是(y-1)(y+5),写清楚为什么会得出那个结果,
(y+2)(y-2)(y-1)(y+5)平方差计算过程要详细,尤其是(y-1)(y+5),写清楚为什么会得出那个结果,
(y+2)(y-2)(y-1)(y+5)
= (y+2)(y-2)(y+2-3)(y+2+3)
= (y^2-4){(y+2)^2-3^2}
= (y^2-4){y^2+4y+4-9}
= (y^2-4){(y^2+4)+4y-9}
= (y^2-4)(y^2+4)+4y (y^2-4)-9(y^2-4)
= y^4-16 +4y^3-16y^2 -9y^2+36
= y^4+4y^3-25y^2+20
（Y-1）*（Y+5）=[(Y+2)-3]*[(Y+2)+3]=(Y+2)^2-3^2
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y(y-2)²-y(y+3)(y-5) y=1/2 化简求值
y (3y^2+8y-3)-6y(3y+2y-1)+9y
5y∧2-(y-2)(3y+1)-2(y+1)(y-5)
解方程3y^2-(2y+1)(y-2)=(y-5)(y-1)
解方程：3y^2-(2y+1)(y-1)=(y-5)(y+1)
解方程：3y²-(2y+1)(y-2)=(y-5)(y+1)
2(y-4)(3y+2)-5(-3y+7)(y+1),其中y=-1
(y平方+2y)(y平方+2y+2)+1
方程y''=(1+y'*y')/2y的通解
y-y-1/2=2-y+5/5一元一次方程
1/2y+1=4y-2/5-y
y-(y-1)/2=1-(2y-3)/5
y-y-1/2=3-y+2/5
y-2分之y-1=-5分之y+2
解方程y-[3y-1]等于5【y+2]
y'=1+y^2