int i;int x[3] [3]={1,2,3,4,5,6,7,8,9}int i;int x[3] [3]={1,2,3,4,5,6,7,8,9},则下面语句的输出结果是_____for(i=0;i

C语言问题int x=3;incre();main(){ int i; for (i=1;i int x=3;main(){int i;for(i=1;i int x=3;main(){int i;for(i=1;i int*a[3] for(int i=0;i>ba[i]=new int[b] } 写出下列每个函数的功能 共3题 (1) int WC(int a[ ],int n,int k) {int c=0;for(int i=0;i=k) c++;return c;}函数功能：(2) bool SG(int x) { //x为大于等于2的整数for(int i=2;ia[i].name>>a[i].age>>a[i].pay;}函数功能： int x=20; int i=2; while(i #include using namespace std; int main() { int a,b,c; a=3; int f(int x,int y,int z);#include using namespace std; int main() {int a,b,c;a=3;int f(int x,int y,int z); cin>>a>>b>>c;c=f(a,b,c);cout int x=3; while(x +2!+3!+.+N!的算法,void fun(int n){int temp = 1;int sum = 0;int i;for (i=0;i 正确的应该怎么编,还有具体的解释,#includeclass Coord {public:void setCoord(int a,int b){ x=a; y=b; }int getx(){ return x; }int gety(){ return y; }private:int x,y;};void main(){ Coord op1;int i,j;op1.x=3;op1.y=4;op1.setCoord(5,6); // 调 #include void main( ) { int a=3,b=5; int *p,*q; void f1(int x,int y);void f2(int *x,int *y);p=&a; q=&b;f1(*p,*q) ;printf(a=%d ,b=%d ,a,b);f2(p,q);printf(a=%d ,b=%d ,a,b);}void f1(int x,int y) { int t;t=x; x=y; y=t;}void f2(int *x,int *y) { int 一个关于C语言指针的问题,源程序：#include intmain(){int a[5]={1,2,3,4,5};int *ptr1=(int *)(&a+1);int *ptr2=(int *)((int)a+1);printf(%x,%x,ptr1[-1],*ptr2);return 0;} 1.28 C语言,int x[3][2]={0},i;for(i=0;i #includeint a(int x);int b(int y);int main(){int m,n;n=6;m=a(n);printf(%d ,m);return 0;}int a(int x){x=b(x+3);return x;}int b(int y){return y+1;} 下列数组定义错误的是 A.int x=5,a[x]; B.int aa[1]; C.int aa[2][3]; D.int a['a']; 代码如下：a.h文件extern int p_abs(int &a);extern int p_max(int &a,int &b);class a{public:a():x(0),y(0){}a(const int &i,const int &j):x(i),y(j){}int get_x(){return x;};int get_y(){return y;};void set_x(const int &i){x=i;};void set_y(const int & main() { int x=1,y=2,z=3; int r; r=func(x+y+z,x++,++y); printf(%d,r); } int func(int a,int b,intint func(int a,int b,int c){int d;d=a+b+c;return d;} #define N 20 fun(int a[],int n,int m) {int i; for(i=m;i>n;i--)a[i+1]=a[i]; return m; } void main() #define N 20fun(int a[],int n,int m){int i;for(i=m;i>n;i--)a[i+1]=a[i];return m;}void main(){ int i,a[N]={1,2,3,4,5,6,7,8,9,10};fun(a,0,N/2);for(i=0;i