y^2=xy=x^2
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y^2=xy=x^2
y^2=x
y=x^2
y^2=xy=x^2
y=x²
则y²=x^4=x
x(x³-1)=0
x(x-1)(x²+x+1)=0
x²+x+1=0无解
所以x=0,x=1
y=x²
所以
x=0,y=0
x=1,y=1
(-3x^y+2xy)-( )=4x^+xy
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