(2x^2+5x-2)/(2x-1)=x+( )求括号里式子?
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(2x^2+5x-2)/(2x-1)=x+( )求括号里式子?
(2x^2+5x-2)/(2x-1)=x+( )求括号里式子?
(2x^2+5x-2)/(2x-1)=x+( )求括号里式子?
(2x² + 5x - 2)/(2x - 1)
= (2x² - x + 6x - 2)/(2x - 1)
= (2x² - x)/(2x - 1) + (6x - 2)/(2x - 1)
= x + (6x - 2)/(2x - 1)
所以括号里的式子是 (6x - 2)/(2x - 1)
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