[(x+y)(x-y)-(x-y)^2-4xy]/2y,其中x=1,y=-1
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[(x+y)(x-y)-(x-y)^2-4xy]/2y,其中x=1,y=-1
[(x+y)(x-y)-(x-y)^2-4xy]/2y,其中x=1,y=-1
[(x+y)(x-y)-(x-y)^2-4xy]/2y,其中x=1,y=-1
[(x+y)(x-y)-(x-y)²-4xy]/2y
=[x²-y²-(x²-2xy+y²)-4xy]/2y
=[x²-y²-x²+2xy-y²-4xy]/2y
=[-2y²-2xy]/2y
=-y-x
=1-1
=0
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化简:[(x+y)(x-y)(x+y)^2-2y(x-2y)](-2y) 谢谢!