若f(x)=ax^5+bx³+dx+8,f(-5)=8,则f(5)____?

若f(x)=ax^5+bx³+dx+8,f(-5)=8,则f(5)____?
若f(x)=ax^5+bx³+dx+8,f(-5)=8,则f(5)____?

若f(x)=ax^5+bx³+dx+8,f(-5)=8,则f(5)____?
因为f（-5）=（-5）^5a+（-5）³b-5d+8=8
得（-5）^5a+（-5）³b-5d=0
所以
f（5）=5^5*a+5³b+5d+8
=-[（-5）^5a+（-5）³b-5d]+8
=8

f(5)=8,因为f(-5)=a*(-5)^5＋b*(-5)^3＋d*(-5)＋8=8,所以-a*5^5-b*5^3-d*5=0,3a*5^5＋b*5^3＋d*5=0,所以f(5)=8