x^2+y^2=64 (8-x)^2+(y-4)^2=16 怎么解的?我求出来是 一个方程两个未知数,就求不下去了

x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y) 【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2= (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z （x+2y)(x-2y)-(2y-x)(-2x-y)其中x=8,y=-8 [(x+2y)(x-2y)-(x-2y)^2+8y(x+y)]除以4x= x*x+2x-y*y+6y-8=0,x+y不等于2,求x-y的值 已知X*X+Y*Y+6X-8Y+25=0 求（Y/X)+(X/Y)-2=? 12y(x-y)^2-8(x-y)^3=? [(2x-y)^2-y(y-4x)-8x]其中x=-1/2 填空：x-y/x+y=( )/x^2-y^2 因式分解x(x+y)(x-y)-x(x+y)^2 （x-y)2•(y-x)³(x-y)=? 9y=3x-(x-1),4(x+y)-(2x+4)=8y 已知x+y/x=11/8,求x-y/x+2y的值 化简(2x/(x+y)-4x/(y-x))/8x(x^2-y^2)得 【x+_2y】[x-2y]-[2x-y][-2x-y]x=8 y=-8 y=x^2-2x（x