数列{an}满足a1=a ,a(n+1)=c×an +1-c ,n为正整数,c和a为实数,且c不等于0.(1)求{an}通项公式(2)设a=1/2 ,c=1/2 ,bn = n×(1-an),求数列{bn}的前n项和Sn
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数列{an}满足a1=a ,a(n+1)=c×an +1-c ,n为正整数,c和a为实数,且c不等于0.(1)求{an}通项公式(2)设a=1/2 ,c=1/2 ,bn = n×(1-an),求数列{bn}的前n项和Sn
数列{an}满足a1=a ,a(n+1)=c×an +1-c ,n为正整数,c和a为实数,且c不等于0.
(1)求{an}通项公式
(2)设a=1/2 ,c=1/2 ,bn = n×(1-an),求数列{bn}的前n项和Sn
数列{an}满足a1=a ,a(n+1)=c×an +1-c ,n为正整数,c和a为实数,且c不等于0.(1)求{an}通项公式(2)设a=1/2 ,c=1/2 ,bn = n×(1-an),求数列{bn}的前n项和Sn
1.a(n+1)=can+1-c
a(n+1)-1=c(an-1)
[a(n+1)-1]/(an-1)=c
数列an-1=(a-1)*c^(n-1)
an=(a-1)*c^(n-1)+1
2.
bn=n*[1-(-1/2*(1/2)^(n-1)-1]=n*(1/2)^n
sn=自己求
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