(1)x^4y^4-2x^2y^2+1(2)多项式x^2-4y^2,与x^2+4xy+4y^2的公因式是( )A.X^2-4Y^2 B.X+2Y C.X-2Y D(X+2Y)(X-2Y)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 20:00:27
(1)x^4y^4-2x^2y^2+1(2)多项式x^2-4y^2,与x^2+4xy+4y^2的公因式是( )A.X^2-4Y^2 B.X+2Y C.X-2Y D(X+2Y)(X-2Y)
(1)x^4y^4-2x^2y^2+1
(2)多项式x^2-4y^2,与x^2+4xy+4y^2的公因式是( )
A.X^2-4Y^2 B.X+2Y C.X-2Y D(X+2Y)(X-2Y)
(1)x^4y^4-2x^2y^2+1(2)多项式x^2-4y^2,与x^2+4xy+4y^2的公因式是( )A.X^2-4Y^2 B.X+2Y C.X-2Y D(X+2Y)(X-2Y)
x^4y^4-2x^2y^2+1
=(x²y²-1)²
=(xy+1)²(xy-1)²
x^2-4y^2
=(x+2y)(x-2y)
x^2+4xy+4y^2
=(x+2y)²
所以选B
答案为B
x²-4y²=(x+2y)(x-2y)
x²+4xy+4y²=(x+2y)²
2。B
x^2-4y^2=(x+2y2)(x-2y2)
x^2+4xy+4y^2=(x+2y)2
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
(x/x+y +2y/x+y)乘以xy/ x+2y除以(1/x+1/y)(2)(3x^2/4y)^2乘以2y/3x+ x^2/2y^2除以2y^2/x
若x+y=4,则多项式1/2(x+y)+4(x-y)-3(x-y)-3/2(x+y)-x+y值是()
(2X-Y)²-4(X-Y)*(X+Y)-(X-Y)*(X-1)
把4(x-y+1)+y(y-2x)因式分解
y(y+2)+4x(x-y-1)因式分解是多少
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
把(x+y),(x-y)个作为一个整体合并同类项1,7(x+y)-2(x+y)-4(x+y)+2(x+y)2,(x-y)²+2(x-y)-(x-y)-2(x-y)²
(x²-4y²)÷(2x+y)/xy×1/x(2y-x)(2x+y)/xy 1/x(2y-x) 都是一项
把下列各式因式分解 (1)、a^2(x-y)-4a(y-x)+4(x-y) (2)、(x+y)(x-y)-(x+z)(x-z)
计算:(4xy(x-y)^-1+(x(y^-1)-(x^-1)y)/((x^-1)+(y^-1)))*(x+y)^-2
x+y+2(-x-y+1)=3(1-y-x)-4-(y+x-1),x+y=?
因式分解:-1/2*x*x*x*y+1/4*x*x*y*y-1/8*x*x*x*y*y*y
化简求值:【(x+Y)(X-Y)-(X-Y)的平方+2Y(2-Y)】除4Y,其中X=1 Y=2
2(x+y)-(x-3y)=13 4(x+y)+3(x-3y)=1解方程组 2(x+y)-(x-3y)=13 4(x+y)+3(x-3y)=1
计算:1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8x^7/(x^8+y^8)
先化简 再求值 (2x-y)(y+x)-(x-2y)(2y+x)-(-3y+x)^2其(√x+1)+y^2+4=-4y
已知:【(x²+y²)-(x-y)²+2y(x-y)】/4y=1,求4x/4x²-y²-1/2x+y