x^2+3y^2+4z^2=2,求|x+3y+4z|小于等于4.
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x^2+3y^2+4z^2=2,求|x+3y+4z|小于等于4.
x^2+3y^2+4z^2=2,求|x+3y+4z|小于等于4.
x^2+3y^2+4z^2=2,求|x+3y+4z|小于等于4.
X+3Y+4Z|2=x2+9y2+16z2+6xy+8xz+24yz
≤x2+9y2+16z2+3(x2+y2)+4(x2+z2)+24(y2+z2)
=8(x2+3y2+4z2)=16
所以 |X+3Y+4Z|≤4
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